5x^2+1.4x-2=0

Solution for 5x^2+1.4x-2=0 equation:

5x^2+1.4x-2=0

a = 5; b = 1.4; c = -2;
Δ = b2-4ac
Δ = 1.42-4·5·(-2)
Δ = 41.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{41.96}}{2*5}=\frac{-1.4-\sqrt{41.96}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{41.96}}{2*5}=\frac{-1.4+\sqrt{41.96}}{10}
$